如何在pydev中声明变量的类型? [英] how to declare variable's type in pydev?

问题描述

假设有一组类 Map1,Map2,Map3,... 都是从 BaseMap 扩展而来的，我使用一些反射机制来获取子 Map 的实例.我想动态获取这些类之一的实例并将其存储在变量 m 中，并让 pydev 将该类型识别为 BaseMap，以便我可以在其上使用单词补全.

Suppose there's a set of class Map1,Map2,Map3,... all extended from BaseMap, and I use some reflection mechanism to get the child Map's instance. I want to dynamically get an instance of one of these classes and store it in a variable m, and have pydev recognize the type as BaseMap so I can use word completion on it.

我发现一种解决方案是添加代码

I found one solution is to add the code

if False:
    m = BaseMap(0,0,0)

在分配 m 之后和使用它之前.if 条件中的那行永远不会被执行，但它声明 m 是一个 BaseMap 类型对象.

after assigning m and before using it. The line inside the if condition would never be executed, but it declares m is a BaseMap type object.

这可能看起来很傻，但确实有效.还有其他方法吗?

This may look silly, but it did work. Is there any other way to do it?

推荐答案

您可以使用 assert isinstance(...) 在 pydev 中对变量进行自动完成，否则 pydev 将无法猜测正确的类型.

You can use assert isinstance(...) to get autocompletion in pydev on variables where otherwise pydev would not be able to guess the correct type.

说你的代码是:

m = getAttr(someThing, 'someAttr')
m.*no autocompletion*

pydev 无法知道 m 的类型，因此不会显示自动完成.

pydev would not be able to know the type of m and therefore won't show the autocompletion.

试试:

m = getAttr(someThing, 'someAttr')
assert isinstance(m, BaseMap) # or whatever class it is
m.*pydev shows autocompletion*

这有点hacky，但它会起作用(而且不会造成伤害).

It's somewhat hacky, but it will work (and also does not hurt).

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