Pygame-两个显示同时更新，中间有一个 pygame.time.wait() 函数 [英] Pygame-Two display updates at the same time with a pygame.time.wait() function between

问题描述

我在两次显示更新之间添加了一个 pygame.time.wait(2000) 函数，期望在按下键后，它会首先显示一个文本，然后在 2 秒后显示第二个文本.但它最终会在触发后两秒同时显示两个文本.我应该如何正确使用该功能来达到我的目标?

I add a pygame.time.wait(2000) function between two display updates expecting that after a keydown, it will first show up one text, then after 2 seconds, the second one. But it end up showing up the two texts simultaneously two seconds after the trigger. How should I correctly use the function to reach my goal?

import pygame
from pygame.locals import *
from sys import exit

SCREEN_WIDTH = 448
SCREEN_HEIGHT = 384

pygame.init()
screen = pygame.display.set_mode([SCREEN_WIDTH, SCREEN_HEIGHT])
my_font = pygame.font.SysFont("arial", 16)
textSurfaceObj1 = my_font.render('Hello world!', True, (255,255,255))
textRectObj1 = textSurfaceObj1.get_rect()
textRectObj1.center = (100, 75)
textSurfaceObj2 = my_font.render('Hello world!', True, (255,255,255))
textRectObj2 = textSurfaceObj2.get_rect()
textRectObj2.center = (200, 150)


while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            exit()
        if event.type == KEYDOWN:
            screen.blit(textSurfaceObj1, textRectObj1)
            pygame.display.flip()
            pygame.time.wait(2000)
            screen.blit(textSurfaceObj2, textRectObj2)
            pygame.display.flip()

推荐答案

如果您的代码有效取决于您使用的窗口管理器，但正如您所注意到的，这并不好.

If your code works depends on the window manager you're using, but as you noticed, that's not good.

您需要考虑到您的游戏在循环中运行的事实，并且您为停止循环所做的一切(例如 wait 或 sleep)都不会工作.

You need to wrap your head around the fact that your game runs in a loop, and everything you do to stop the loop (like wait or sleep) will not work.

在您的代码中，您具有三种状态:

In your code, you have three states:

1) 什么也不打印
2)打印第一个文本
3) 打印两个文本

1) print nothing
2) print the first text
3) print both texts

解决问题的简单方法是简单地跟踪变量中的当前状态，如下所示:

so and easy way to solve your problem is to simply keep track of the current state in a variable, like this:

import pygame
from sys import exit

SCREEN_WIDTH = 448
SCREEN_HEIGHT = 384

pygame.init()
screen = pygame.display.set_mode([SCREEN_WIDTH, SCREEN_HEIGHT])
my_font = pygame.font.SysFont("arial", 16)

text = my_font.render('Hello world!', True, (255,255,255))
text_pos1 = text.get_rect(center=(100, 75))
text_pos2 = text.get_rect(center=(200, 150))

state = 0
ticks = None
while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            exit()
        if event.type == pygame.KEYDOWN and state == 0:
            state = 1
            ticks = pygame.time.get_ticks()

    if state == 1 and ticks and pygame.time.get_ticks() > ticks + 2000:
        state = 2

    screen.fill((30, 30, 30))
    if state > 0: screen.blit(text, text_pos1)
    if state > 1: screen.blit(text, text_pos2)
    pygame.display.flip()

这篇关于Pygame-两个显示同时更新，中间有一个 pygame.time.wait() 函数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！