生成多个相同的精灵 [英] Spawning Multiple of the same sprite
问题描述
我目前正在开发一款名为 Table Wars 的游戏，这是一款适用于两名玩家的回合制战略游戏.进展一直很顺利，直到我遇到了生成单位的问题.
I am currently working on a game called Table Wars, a turn based strategy game for two players. Progress has been going smoothly, until I ran into a problem with spawning units.
程序不会生成多个相同的单元，也不会在旧单元死后重新生成新单元.
The program won't spawn multiple of the same unit, or respawn new ones after the old ones die.
以下信息可能会有所帮助:
Here is some information that may help:
- 每个类都存储在一个变量中:(
redI = Red_Infantry()) - 所有函数都存储在主循环中.
- 精灵类具有硬编码的 X 和 Y 值，用于生成单位和移动单位.
我该怎么办?
根据要求，这是红色步兵的课程:
As requested, here is the class for the Red Infantry:
class Red_Infantry(pygame.sprite.Sprite):
def __init__(self):
pygame.sprite.Sprite.__init__(self)
self.image, self.rect = load_image('Soldier_red.png', -1)
self.selected = 0
self.area = screen.get_rect()
self.rect.topleft = (100, 300)
self.health = 100 #Soldiers are have mediocre toughness.
self.attack_damage = 25
self.range_maximum = 20 #in pixels, this is melee range
self.range_minimum = 0
self.update()
def update(self):
if self.health <= 0:
self.kill()
以及生成这个单位的代码:
and the code to spawn this unit:
if spawned_units < 3 and PHASE == 1 and TURN == 'Red':
if REDGOLD < 10:
print "Out of money! Moving to Phase 2!"
PHASE = 2
spawned_units = 0
elif event.type == KEYDOWN and event.key == K_1:
if REDGOLD >= 10 and REDCOMMAND >= 5:
Sprites.append(redI)
REDGOLD -= 10
REDCOMMAND -= 5
spawned_units = spawned_units + 1
else:
print "Not enough gold!"
这与所有单位的风格相似.它在第一次正确执行，但在第二次、第三次等等时都没有正确执行，这意味着我只能有一个士兵.此外，当那个士兵通过 self.kill 死亡时，如果我尝试生成它，它就不会回来.
This is similar style with all units. It performs correctly the first time, but not in the second, third, and so on, meaning I can only have one Soldier. Also, when that soldier dies via self.kill, it won't come back if I try to spawn it.
推荐答案
您发布的部分生成过程不会创建任何新实例.除非在其他地方将 redI 声明为新的 Red_Infantry，否则每次需要修改代码以创建 Red_Infantry 的新实例生成一个士兵.
The part of the spawn procedure you posted doesn't create any new instances. Unless redI is declared as a new Red_Infantry somewhere else, you need to modify the code to create a new instance of Red_Infantry every time you want to spawn a soldier.
sprites.append(Red_Infantry())
更新精灵:
for sprite in sprites:
sprite.update()
将移动和其他状态更改放在更新方法中.这是 pygame 所期望的，但如果您愿意，您可以使用不同的样式.要点是你必须有多个 Red_Infantry 实例才能看到多个精灵.
Put movement and other state changes in the update method. This is what pygame expects, but you can use a different style if you want. The main point is you must have multiple instances of Red_Infantry in order to see multiple sprites.
您也可以使用 pygame 的 Group 类代替用于保存精灵的简单列表.
You could also use pygame's Group class instead of a simple list to hold the sprites.
这是一个使用 Group 而不是列表的完整示例.在这个例子中，每次按下一个键都会产生一个 Enemy.每个 Enemy 将其唯一 ID 打印到标准输出.
Here's a full example that uses Group instead of list. In the example, an Enemy is spawned each time a key is pressed. Each Enemy prints its unique ID to stdout.
import sys
import random
import pygame
from pygame.locals import *
def main():
pygame.init()
screen = pygame.display.set_mode((480, 320))
enemies = pygame.sprite.Group()
while True:
for event in pygame.event.get():
if event.type == KEYDOWN:
enemies.add(Enemy(screen))
elif event.type == QUIT:
sys.exit()
enemies.update()
screen.fill(pygame.Color("black"))
enemies.draw(screen)
pygame.display.update()
class Enemy(pygame.sprite.Sprite):
def __init__(self, screen):
pygame.sprite.Sprite.__init__(self)
print "created a new sprite:", id(self)
self.image = pygame.image.load("sprite.png")
self.rect = self.image.get_rect()
self.rect.move_ip(random.randint(0, screen.get_width()),
random.randint(0, screen.get_height()))
def update(self):
self.rect.move_ip(random.randint(-3, 3), 0)
if __name__ == "__main__":
main()
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