为什么在pygame中文本显示2秒 [英] Why text display for 2 seconds in pygame

问题描述

我显示的文本仅显示约 2 秒.我希望它会在我点击其他区域时显示

Text wchich I display is displaying for only around 2 sec. I want that it will display while I click to other area

elif msg[0:7] == 'YOU WIN' and Message_id == '200':
    print('You Win')
    textSurface = font.render('You Win', True, (0, 0, 0))
    largeText = pygame.font.Font('freesansbold.ttf', 115)
    TextSurf = pygame.font.render('You Win', True, (0, 0, 0))
    TextRect = textSurface.get_rect()
    TextRect.center = ((600 / 2), (700 // 2))
    surface.blit(TextSurf, TextRect)
    grid.draw(surface)
    pygame.display.flip()
    break

推荐答案

如果要永久绘制某些内容，则需要在应用程序循环中绘制它.典型的 PyGame 应用程序循环必须:

If you want something to be drawn permanently, you need to draw it in the application loop. The typical PyGame application loop has to:

• 通过 pygame.event 处理事件.pump() 或 <代码>pygame.event.get().
• 根据输入事件和时间(分别为帧)更新游戏状态和对象位置
• 清除整个显示或绘制背景
• 绘制整个场景(blit 所有对象)
• 通过pygame.display.update() 或 <代码>pygame.display.flip()

在初始化时创建文本表面:

Create the text surface at initialization:

winTextSurf = font.render('You Win', True, (0, 0, 0))
winTextRect = winTextSurf.get_rect(topleft = (600 // 2, 700 // 2)

添加一个变量，表示需要绘制文本:

Add a variable that indicates the text needs to be drawn:

drawWinText = Fasle

如果需要绘制文本，设置变量:

Set the variable if the text needs to be drawn:

elif msg[0:7] == 'YOU WIN' and Message_id == '200':
    drawWinText = True
    break

当您不再希望绘制文本时，您需要重置该值.

When you no longer want the text to be drawn, you need to reset the value.

drawWinText = False

根据drawWinText的状态在主应用循环中绘制文本:

Draw the text in the main application loop depending on the status of drawWinText:

while run:

    # [...]

    if drawWinText:
        surface.blit(winTextSurf, winTextRect)

    pygame.display.flip()

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查看问题的答案Python - Pygame - 渲染半透明文本，了解如何绘制透明文本.

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See the answers to question Python - Pygame - rendering translucent text for how to draw transparent text.

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