如何在 Pygame 中绘制一个半透明的圆圈? [英] How to draw a semi-transparent circle in Pygame?

问题描述

我试图在 Pygame 中绘制一个半透明的圆圈.这是我的代码:

I'm trying to draw a semi-transparent circle in Pygame. Here is my code:

import pygame
pygame.init()
clock = pygame.time.Clock()
screen=pygame.display.set_mode((width,height))

while True:
    msElapsed = clock.tick(100)
    screen.fill((0,0,0,255))
    pygame.draw.circle(screen,(30,224,33,100),(250,100),10)
    pygame.display.update()

    for event in pygame.event.get():
        if event.type==pygame.QUIT:
            exit()

我想使用 RGBA 作为圆形颜色.但是圆圈是全彩色的.我的代码有什么问题?

I want to use RGBA as circle color. But the circle is fully colored. What's the problem with my code?

推荐答案

修复:

首先你需要创建一个接受透明度的表面

First you need to create a surface which accepts transparency

surface = pygame.Surface((width,height), pygame.SRCALPHA)

然后从这一行:

pygame.draw.circle(screen,(30,224,33,100),(250,100),10)

将 screen 更改为 surface 看起来应该是这样的:

CHANGE screen TO surface SO IT SHOULD LOOK LIKE:

pygame.draw.circle(surface,(30,224,33,100),(250,100),10)

然后添加:

screen.blit(surface, (0,0))

说明:

当您在屏幕上绘制圆圈时，它会忽略透明度值，因为 pygame 屏幕无法接受它们.我所做的是创建了一个可以接受透明度的新层/屏幕(由于这个参数 pygame.SRCALPHA)，然后将该层/屏幕粘贴到原始屏幕的顶部.

When you were drawing the circle onto the screen it ignored the transparency values as the pygame screen cannot accept them. What I have done is created a new layer/screen which can accept transparency (due to this argument pygame.SRCALPHA) and then pasted that layer/screen on top of the original screen.

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