填充阵列，数字范围 [英] Fill arrays with ranges of numbers

问题描述

有没有语法/包，它允许Java数组的快速充填数字范围，在Perl？

Is there any syntax/package allowing quick filling of java arrays with ranges of numbers, like in perl?

例如

int[] arr = new int[1000];
arr=(1..500,301..400,1001..1400); // returns [1,2,3,4,...,500,301,302,...,400,1001,1002,...1400]

此外，这里一个包，允许获得在数字作为上述的这种列表中的第n号，而不实际创建阵列（其可以是巨大的）？

Also, it here a package that allows getting the n-th number in such list of numbers as the above, without actually creating the array (which can be huge)?

例如

BunchOfRangesType bort = new BunchOfRangesType("1..500","301..400","1001..1400");
bort.get(0); // return 1
bort.get(500); // return 301
bort.get(501); // return 302

这不是太难以执行，但我想它可能是共同的，所以也许它已经完成。

It's not too difficult to implement, but I guess it might be common so maybe it was already done.

推荐答案

不太一样干净真正的软的答案，但是你可以使用的谷歌番石榴以同样的效果：

Not quite as clean as True Soft's answer, but you can use Google Guava to the same effect:

public class Test {

    public static void main(String[] args) {
        //one liner
        int[] array = toArray(newLinkedList(concat(range(1, 10), range(500, 1000))));

        //more readable
        Iterable<Integer> values = concat(range(1, 10), range(500, 1000));
        List<Integer> list = newLinkedList(values);
        int[] array = toArray(list);

    }

    public static List<Integer> range(int min, int max) {
        List<Integer> list = newLinkedList();
        for (int i = min; i <= max; i++) {
            list.add(i);
        }

        return list;
    }

}

请注意，你需要几个静态进口这个工作。

Note you need a few static imports for this to work.

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