pyqt5 中的连接功能不起作用 [英] connect function in pyqt5 does not work

问题描述

我最近从 pyside 迁移到 pyqt5 并且有问题.我在网上查了一下，显然，它已经发生在使用 pyqt4 并转移到 pyqt5 的人身上.但是，它并没有真正帮助...我尝试在 Qobject 之后添加 pyqtSignal 但它仍然无法正常工作.请帮忙.这些是我的代码行:

QtCore.QObject.connect(self.buttonBox, QtCore.SIGNAL("accepted()"),Dialog.accept)QtCore.QObject.connect(self.buttonBox, QtCore.SIGNAL("rejected()"), Dialog.reject)

这是我运行时出现的:

AttributeError: type object 'QObject' 没有属性 'connect'

解决方案

来自文档:

connect(slot[, type=PyQt5.QtCore.Qt.AutoConnection[, no_receiver_check=False]])

<块引用>

将信号连接到插槽.如果连接失败，将引发异常.参数:

• slot – 要连接的插槽，可以是 Python 可调用信号或其他绑定信号.
• type – 要建立的连接的类型.
• no_receiver_check – 抑制底层 C++ 接收器实例仍然存在的检查，并无论如何传递信号.

<小时>

例如:

self.buttonBox.accepted.connect(Dialog.accept) # pyqt5

<块引用>

QtCore.QObject.connect(self.buttonBox.rejected, Dialog.reject) # pyqt4

_{作为旁注，Dialog"听起来像一个类，您可能想要连接到一个实例，否则考虑使用小写前写字母命名您的实例...}

I recently moved from pyside to pyqt5 and there is a problem. I looked it up online and apparently, it already happened to people who used pyqt4 and moved to pyqt5. However, it didn't really help... I tried to add pyqtSignal after Qobject but it is still not working. Please help. these are my code lines:

QtCore.QObject.connect(self.buttonBox, QtCore.SIGNAL("accepted()"),Dialog.accept)
QtCore.QObject.connect(self.buttonBox, QtCore.SIGNAL("rejected()"), Dialog.reject)

and this is what appears when I run it:

AttributeError: type object 'QObject' has no attribute 'connect'

解决方案

from the docs:

connect(slot[, type=PyQt5.QtCore.Qt.AutoConnection[, no_receiver_check=False]])

Connect a signal to a slot. An exception will be raised if the connection failed. Parameters:

• slot – the slot to connect to, either a Python callable or another bound signal.
• type – the type of the connection to make.
• no_receiver_check – suppress the check that the underlying C++ receiver instance still exists and deliver the signal anyway.

---

for your example:

self.buttonBox.accepted.connect(Dialog.accept) # pyqt5

QtCore.QObject.connect(self.buttonBox.rejected, Dialog.reject) # pyqt4

_{As a sidenote, "Dialog" sounds like a class, you probably want to connect to an instance, else think about naming your instances with lowercase front-letters ...}

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