PyQt4.QtCore.pyqtSignal 对象没有属性“connect" [英] PyQt4.QtCore.pyqtSignal object has no attribute 'connect'

问题描述

我在创建的课程中遇到自定义信号问题.

I'm having issues with a custom signal in a class I made.

相关代码:

self.parse_triggered = QtCore.pyqtSignal()

def parseFile(self):
    self.emit(self.parse_triggered)

这两个都属于类:RefreshWidget.在它的父类中，我有:

Both of those belong to the class: RefreshWidget. In its parent class I have:

self.refreshWidget.parse_triggered.connect(self.tabWidget.giveTabsData())

当我尝试运行程序时，出现错误:

When I try to run the program, I get the error:

AttributeError: 'PyQt4.QtCore.pyqtSignal' object has no attribute 'connect'

帮助?提前致谢.

推荐答案

我和你有同样的问题.

尝试移动

self.parse_triggered = QtCore.pyqtSignal()

在你的构造函数之外，但在你的类声明中.所以，而不是它看起来像这样:

out of your constructor but inside your class declaration. So instead of it looking like this:

class Worker(QtCore.QThread):
    def __init__(self, parent = None):
        super(Worker, self).__init__(parent)

        self.parse_triggered = QtCore.pyqtSignal()

它应该是这样的:

class Worker(QtCore.QThread):
    parse_triggered = QtCore.pyqtSignal()

    def __init__(self, parent = None):
        super(Worker, self).__init__(parent)

这可能根本不是您要找的，但它对我有用.无论如何，我切换回旧式信号，因为我还没有在新式信号中找到具有未定义数量或类型参数的方法.

This might not be at all what you are looking for, but it worked for me. I switched back to old-style signals anyways because I haven't found a way in new-style signals to have an undefined number or type of parameters.

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