避免重复随机 [英] Avoiding random duplicates

问题描述

System.Random generator = new Random(DateTime.Now.Millisecond);
int[] lotteryNumber = new int[7];

Console.WriteLine("Your lottery numbers: ");
for (int i = 0; i<7; i++)
{
    lotteryNumber[i] = generator.Next(1, 37);
    Console.Write("{0} ",lotteryNumber[i]);
}
Console.ReadLine();

我需要做一个打印7开奖号码的程序，但没有重复。在code以上版画在（1-37）范围内7个随机数字，但重复appaer。我需要一种方法来prevent重复号码出现。

I need to make a program that prints 7 lottery numbers, but without duplicates. The code above prints 7 random numbers in the range of (1-37), but duplicates appaer. I need a way to prevent duplicate numbers from appearing.

推荐答案

最简单的办法国际海事组织将生成的序列的所有的可能数量（即1-37），洗牌的收集，再取前七个结果。

The simplest approach IMO would be to generate a sequence of all the possible numbers (i.e. 1-37), shuffle the collection, then take the first seven results.

搜索堆栈溢出的费雪耶茨洗牌C＃会发现很多的例子。

Searching on Stack Overflow for "Fisher-Yates shuffle C#" will find lots of examples.

在事实上，你可以修改费雪耶茨洗牌，你带他们到产生结果，所以你可以写一个方法，如：

In fact, you could modify the Fisher-Yates shuffle to yield results as you took them, so you could write a method such as:

var numbers = Enumerable.Range(1, 37).Shuffle().Take(7).ToList();

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