pyqt 自动连接信号 [英] pyqt auto connect signal

问题描述

我想使用自动连接功能.我正在使用这个例子:

I want use the autoconnection feature. I am using this example:

http://www.eurion.net/python-snippets/snippet/Connecting%20signals%20and%20slots.html

它有效，但我想创建自己的信号和插槽，示例使用内置信号.

it works, but I want to create my own signals and own slots, the example using built in signals.

例如，这里有一个带有自定义槽的自定义信号，但不起作用:

for example, here are a custom signal with a custom slot, but don't works:

import sys
from PyQt4 import QtGui, QtCore

class SignalsAndSlots(QtGui.QWidget):

    testSignal = QtCore.pyqtSignal(str,name='testSignal')  



    def __init__(self):
        QtGui.QMainWindow.__init__(self)
        self.setObjectName('testObject')
        self.label = QtGui.QLabel(self)

        QtCore.QMetaObject.connectSlotsByName(self)
        self.emitSignal()


    def emitSignal(self):
        self.testSignal.emit('message')  

    @QtCore.pyqtSlot(str,name='on_testObject_testSignal')     
    def autoSlot(self,msg):
        self.label.setText(msg)

if __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)
    gui = SignalsAndSlots()
    gui.show()
    app.exec_()

非常感谢

推荐答案

Ber 是对的.这就是 pyqt 文档 所说的:

Ber is right. This what the pyqt documentation says:

QMetaObject.connectSlotsByName 递归搜索给定对象的所有子对象 [...]

QMetaObject.connectSlotsByName searches recursively for all child objects of the given object [...]

这是一个带有自定义信号的简单示例:

Here is a simple example with custom signals :

import sys
from PyQt4 import QtGui, QtCore

class CustomButton(QtGui.QPushButton):
    custom_clicked = QtCore.pyqtSignal(str, name='customClicked')
    def mousePressEvent(self, event):
        self.custom_clicked.emit("Clicked!")

class SignalsAndSlots(QtGui.QWidget):

    def __init__(self):
        QtGui.QMainWindow.__init__(self)
        layout = QtGui.QHBoxLayout(self)
        self.custom_button = CustomButton("Press Me", self)
        self.custom_button.setObjectName('customButton')
        self.label = QtGui.QLabel("Nothing...", parent=self)
        layout.addWidget(self.custom_button)
        layout.addWidget(self.label)
        QtCore.QMetaObject.connectSlotsByName(self)

    @QtCore.pyqtSlot(str, name='on_customButton_customClicked')     
    def autoSlot(self, msg):
        self.label.setText(msg)

if __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)
    gui = SignalsAndSlots()
    gui.show()
    app.exec_()

但我认为您应该考虑不使用对象名称.新型信号连接方式更简洁.这是相同的应用程序:

But I think you should consider not using the object names. New-style signal connection is way neater. Here is the same application :

import sys
from PyQt4 import QtGui, QtCore

class CustomButton(QtGui.QPushButton):
    custom_clicked = QtCore.pyqtSignal(str)
    def mousePressEvent(self, event):
        self.custom_clicked.emit("Clicked!")

class SignalsAndSlots(QtGui.QWidget):

    def __init__(self):
        QtGui.QMainWindow.__init__(self)
        layout = QtGui.QHBoxLayout(self)
        self.custom_button = CustomButton("Press Me", self)
        self.custom_button.setObjectName('customButton')
        self.label = QtGui.QLabel("Nothing...", parent=self)
        layout.addWidget(self.custom_button)
        layout.addWidget(self.label)
        self.custom_button.custom_clicked.connect(self.on_clicked)

    def on_clicked(self, msg):
        self.label.setText(msg)

if __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)
    gui = SignalsAndSlots()
    gui.show()
    app.exec_()

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