参数 1 具有意外类型“NoneType"? [英] Argument 1 has unexpected type 'NoneType'?

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本文介绍了参数 1 具有意外类型“NoneType"?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我的 PyQt 按钮操作有问题.我想发送一个带有函数的字符串,但出现此错误:

I have a problem with my PyQt button action. I would like to send a String with the Function but I got this Error:

TypeError: 参数 1 具有意外类型 'NoneType'

TypeError: argument 1 has unexpected type 'NoneType'

import sys

from PyQt5.QtWidgets import QApplication, QPushButton, QAction
from PyQt5.QtCore import QObject, pyqtSignal
from PyQt5.QtGui import *
from PyQt5.uic import *

app = QApplication(sys.argv)
cocktail = loadUi('create.ui')

def mixCocktail(str):
      cocktail.show()
      cocktail.showFullScreen()
      cocktail.lbl_header.setText(str)


widget = loadUi('drinkmixer.ui')

widget.btn_ckt1.clicked.connect(mixCocktail("string"))

widget.show()
sys.exit(app.exec_())

推荐答案

正如 user3030010ekhumoro 它需要一个可调用的函数.在这种情况下,您应该用 lambda: mixCocktail("string") 替换该参数AND ALSO 不要使用 str 它是 python 内置数据类型我已经用 _str

As suggested by user3030010 and ekhumoro it expects a callable function. In which case you should replace that argument with lambda: mixCocktail("string") AND ALSO don't use str it's a python built-in datatype I have replaced it with _str

import sys

from PyQt5.QtWidgets import QApplication, QPushButton, QAction
from PyQt5.QtCore import QObject, pyqtSignal
from PyQt5.QtGui import *
from PyQt5.uic import *

app = QApplication(sys.argv)
cocktail = loadUi('create.ui')

def mixCocktail(_str):
      cocktail.show()
      cocktail.showFullScreen()
      cocktail.lbl_header.setText(_str)
      

widget = loadUi('drinkmixer.ui')

widget.btn_ckt1.clicked.connect(lambda: mixCocktail("string"))

widget.show()
sys.exit(app.exec_())

有关 lambda 函数的更多信息:什么是 lambda(函数)?

More about lambda functions: What is a lambda (function)?

这篇关于参数 1 具有意外类型“NoneType"?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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