PySide/等待或睡眠 [英] PySide / wait or sleep

问题描述

我是 python 和 pyside 的新手.我将尝试成功运行以下代码.但现在我希望程序在显示窗口后等待用户无法使用它的定义时间，然后升级状态栏.我会尝试 sleep() 但不知道它必须以正确的方式放置在代码中的哪个位置.感谢您的帮助.

i´m new to python and pyside. I´ll try to run the following code with success. But now i want the programm to wait after showing up the window for a defined time where the user can´t use it and then upgrade the statusbar. i´ll tried sleep() but have no idea where it had to be placed the correct way in the code. Thanks for help.

#!/usr/bin/python
# -*- coding: utf-8 -*-

"""
ZetCode PySide tutorial 

This program creates a statusbar.

author: Jan Bodnar
website: zetcode.com 
last edited: August 2011
"""

import sys, time
from PySide import QtGui

class Main(QtGui.QMainWindow):

    def __init__(self):
        super(Main, self).__init__()

        self.initUI()

    def initUI(self):               

    exitAction = QtGui.QAction(QtGui.QIcon('exit.png'), '&Exit', self)
    exitAction.setShortcut('Ctrl+Q')
    exitAction.setStatusTip('Exit application')
    exitAction.triggered.connect(self.close)        

    self.statusBar().showMessage('no connection')

    menubar = self.menuBar()
    fileMenu = menubar.addMenu('&File')
    fileMenu.addAction(exitAction)

    self.setGeometry(100, 100, 400,300)
        self.setWindowTitle('Main')    
        self.show() 

def main():

    app = QtGui.QApplication(sys.argv)
    ex = Main()
    sys.exit(app.exec_())


if __name__ == '__main__':
    main()

推荐答案

不要使用 sleep.Sleep 只会阻塞活动的事件循环，用户仍然可以点击 GUI 中的任意位置，并且事件将在 sleep 返回后延迟传递.

Don't use sleep. Sleep will only block the active event loop, the user can still click anywhere in the GUI and the events will be delivered delayed after sleep has returned.

如果您想禁用用户交互，请禁用小部件(并使用计时器重新启用它).您的案例中的一个简单示例可能如下所示:

If you want to disable user interaction, then disable the widget (and use a timer to reenable it). A simple example in your case could look like this:

...
def main():
    app = QtGui.QApplication(sys.argv)
    ex = Main()
    ex.setEnabled(False)
    QtCore.QTimer.singleShot(4000, lambda: es.setEnabled(True))
    sys.exit(app.exec_())
...

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