pytest中参数的笛卡尔乘积的参数化测试 [英] parameterized test with cartesian product of arguments in pytest

问题描述

只是想知道，有没有(更)优雅的笛卡尔积参数化方法?这是我目前想到的:

Just wondering, is there any (more) elegant way of parameterizing with the cartesian product? This is what I figured out so far:

numbers    = [1,2,3,4,5]
vowels     = ['a','e','i','o','u']
consonants = ['x','y','z']

cartesian = [elem for elem in itertools.product(*[numbers,vowels,consonants])]

@pytest.fixture(params=cartesian)
def someparams(request):
  return request.param

def test_something(someparams):
  pass

至少我想在fixture函数中封装数字、元音、辅音和笛卡尔.

At least I'd like to encapsulate numbers, vowels, consonants and cartesian in the fixture function.

推荐答案

我可以想到两种方法来做到这一点.一种使用参数化的装置，一种参数化测试函数.由您决定哪一种更优雅.

I can think of two ways to do this. One uses parametrized fixtures, and one parametrizes the test function. It's up to you which one you find more elegant.

这是参数化的测试函数:

Here is the test function parametrized:

import itertools
import pytest

numbers = [1,2,3,4,5]
vowels = ['a','e','i','o','u']
consonants = ['x','y','z']


@pytest.mark.parametrize('number,vowel,consonant',
    itertools.product(numbers, vowels, consonants)
)
def test(number, vowel, consonant):
    pass

值得注意的是，parametrize 装饰器的第二个参数可以是一个可迭代对象，而不仅仅是一个列表.

Of note, the second argument to the parametrize decorator can be an iterable, not just a list.

这是通过参数化每个灯具来实现的:

Here is how you do it by parametrizing each fixture:

import pytest

numbers = [1,2,3,4,5]
vowels = ['a','e','i','o','u']
consonants = ['x','y','z']


@pytest.fixture(params=numbers)
def number(request):
    return request.param

@pytest.fixture(params=vowels)
def vowel(request):
    return request.param

@pytest.fixture(params=consonants)
def consonant(request):
    return request.param


def test(number, vowel, consonant):
    pass

你的直觉是对的.通过参数化多个装置中的每一个，pytest 负责创建所有出现的排列.

Your intuition was correct. By parametrizing each of multiple fixtures, pytest takes care of creating all the permutations that arise.

测试输出是相同的.这是一个示例(我使用 -vv 选项运行 py.test):

The test output is identical. Here is a sample (I ran py.test with the -vv option):

test_bar.py:22: test[1-a-x] PASSED
test_bar.py:22: test[1-a-y] PASSED
test_bar.py:22: test[1-a-z] PASSED
test_bar.py:22: test[1-e-x] PASSED
test_bar.py:22: test[1-e-y] PASSED
test_bar.py:22: test[1-e-z] PASSED
test_bar.py:22: test[1-i-x] PASSED

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