使用 pytest 对参数化基准进行分组 [英] Grouping Parametrized Benchmarks with pytest

问题描述

我目前正在对我使用

有谁知道我可以对输出进行分组的方法，但可以说是我示例中的 case?或者更好的是，通过 (case,n) 元组?

解决方案

一个有用的评论 说 pytest 的 master 分支正在支持这个确切的功能，但我无法让它工作(下一个版本交叉手指).>

与此同时，我想出了这个方便的解决方法.我可以使用这种方法按 case 分组，但不能按 (case,n) 分组.我在每个测试用例上方添加了一个 @benchmark_this 装饰器来包装 benchmark 调用.即使没有按测试用例分组的额外好处，它也非常方便！

def benchmark_this(test):定义包装器(基准，t，n):基准(测试，无，t，n)返回包装器类型 = [BaseTree, AvlTree]尺寸 = [100,300,1000]@pytest.mark.parametrize('t', 类型)@pytest.mark.parametrize('n', 尺寸)@benchmark_thisdef test_insertRandomOrder(benchmark, t, n):随机种子(0x1C2C6D66)树 = t()对于范围(n)中的我:tree.insert(random.randint(0, 0x7FFFFFFF), i)@pytest.mark.parametrize('t', 类型)@pytest.mark.parametrize('n', 尺寸)@benchmark_thisdef test_insertDescendingOrder(benchmark, t, n):树 = t()对于范围(n)中的我:tree.insert(n-i, i)# ...

用

调用<块引用>

py.test --benchmark-group-by=func

I'm currently benchmarking an implementation of an AVL Tree I made against a non-rebalancing binary search tree using pytest-benchmark. It seems to be working well for me so far but I've run into an issue. In order to consolidate the test file, I found that I can parametrize tests and also group the output of the benchmark for readability but I can't seem to do them both at the same time.

My current insertion benchmark:

# always the same for repeatability
random.seed(0x1C2C6D66)

def insertRandomOrder(t, n):
  tree = t()
  for i in range(0,n):
    tree.insert(random.randint(0,0x7FFFFFFF),i)

def insertDescendingOrder(t, n):
  tree = t()
  for i in range(0,n):
    tree.insert(n-i,i)

def insertOutInOrder(t, n):
  tree = t()
  for i in range(0,n):
    idx = (i%2)*n + (1-2*(i%2))*i
    tree.insert(idx,i)

def insertAscendingOrder(t, n):
  tree = t()
  for i in range(0,n):
    tree.insert(i,i)

types = [BaseTree, AvlTree]
sizes = [100,300,1000]
cases = [insertAscendingOrder, insertDescendingOrder, insertOutInOrder, insertRandomOrder]

@pytest.mark.parametrize('t', types)
@pytest.mark.parametrize('n', sizes)
@pytest.mark.parametrize('case', cases)
def test_insert_benchmark(benchmark, t, n, case):
  benchmark(case, t, n)

And here is the output:

Does anyone know of a way where I could group the output but say, the case from my example? Or better yet, by a (case,n) tuple?

解决方案

There was a useful comment saying that the master branch of pytest is in the process of supporting this exact feature, but I was unable to get it to work (fingers crossed for next release).

In the meantime, I figured out this handy work around. I'm able to group by case, but not by (case,n) with this method. I added a @benchmark_this decorator above each test case to wrap the benchmark call. It's pretty handy even without the extra benefit of grouping by test case!

def benchmark_this(test):
  def wrapper(benchmark, t, n):
    benchmark(test, None, t, n)
  return wrapper

types = [BaseTree, AvlTree]
sizes = [100,300,1000]

@pytest.mark.parametrize('t', types)
@pytest.mark.parametrize('n', sizes)
@benchmark_this
def test_insertRandomOrder(benchmark, t, n):
  random.seed(0x1C2C6D66)
  tree = t()
  for i in range(n):
    tree.insert(random.randint(0, 0x7FFFFFFF), i)

@pytest.mark.parametrize('t', types)
@pytest.mark.parametrize('n', sizes)
@benchmark_this
def test_insertDescendingOrder(benchmark, t, n):
  tree = t()
  for i in range(n):
    tree.insert(n-i, i)

# ...

Invoked with

py.test --benchmark-group-by=func

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