出现重叠的字符串计数 [英] String count with overlapping occurrences

问题描述

计算给定字符串出现次数(包括 Python 中的重叠)的最佳方法是什么?这是一种方式:

What's the best way to count the number of occurrences of a given string, including overlap in Python? This is one way:

def function(string, str_to_search_for):
      count = 0
      for x in xrange(len(string) - len(str_to_search_for) + 1):
           if string[x:x+len(str_to_search_for)] == str_to_search_for:
                count += 1
      return count


function('1011101111','11')

此方法返回 5.

Python 中有更好的方法吗?

Is there a better way in Python?

推荐答案

嗯，这可能更快，因为它在 C 中进行比较:

Well, this might be faster since it does the comparing in C:

def occurrences(string, sub):
    count = start = 0
    while True:
        start = string.find(sub, start) + 1
        if start > 0:
            count+=1
        else:
            return count

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