如何在 Python 中找到与正则表达式的所有匹配项? [英] How can I find all matches to a regular expression in Python?

问题描述

在我正在编写的程序中，我让 Python 使用 re.search() 函数在文本块中查找匹配项并打印结果.但是，一旦在文本块中找到第一个匹配项，程序就会退出.

In a program I'm writing I have Python use the re.search() function to find matches in a block of text and print the results. However, the program exits once it finds the first match in the block of text.

如何在找到所有匹配项之前程序不会停止的情况下重复执行此操作?是否有单独的函数来执行此操作?

How do I do this repeatedly where the program doesn't stop until ALL matches have been found? Is there a separate function to do this?

推荐答案

使用 re.findall 或 re.finditer 代替.

re.findall(pattern, string) 返回匹配字符串的列表.

re.findall(pattern, string) returns a list of matching strings.

re.finditer(pattern, string) 在 MatchObject 对象.

re.finditer(pattern, string) returns an iterator over MatchObject objects.

示例:

re.findall( r'all (.*?) are', 'all cats are smarter than dogs, all dogs are dumber than cats')
# Output: ['cats', 'dogs']

[x.group() for x in re.finditer( r'all (.*?) are', 'all cats are smarter than dogs, all dogs are dumber than cats')]
# Output: ['all cats are', 'all dogs are']

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