初始化交错数组的LINQ路 [英] Initialize a Jagged Array the LINQ Way

问题描述

我有一个二维交错数组（虽然它总是矩形），我初始化采用传统的循环：

  VAR myArr，该=新的双[rowCount等] [];
的for（int i = 0; I＆LT; rowCount时，我++）{
    myArr，该由[i] =新的双[colCount]
}
 

我想，也许有些LINQ功能都会给我一种优雅的方式在一个语句来做到这一点。不过，我可以拿出最接近的是这样的：

 双击[] [] myArr，该= Enumerable.Repeat（新双[colCount]，rowCount等）.ToArray（）;
 

问题是，它似乎已创造了一个单一的双击[colCount] 并分配为每行一个新的数组的intsead分配引用。有没有办法做到这一点没有得到太神秘？

解决方案

 双击[] [] myArr，该=可枚举
  .Range（0，rowCount等）
  。选择（I =＆gt;新建双[colCount]）
  .ToArray（）;
 

I have a 2-dimensional jagged array (though it's always rectangular), which I initialize using the traditional loop:

var myArr = new double[rowCount][];
for (int i = 0; i < rowCount; i++) {
    myArr[i] = new double[colCount];
}

I thought maybe some LINQ function would give me an elegant way to do this in one statement. However, the closest I can come up with is this:

double[][] myArr = Enumerable.Repeat(new double[colCount], rowCount).ToArray();

The problem is that it seems to be creating a single double[colCount] and assigning references to that intsead of allocating a new array for each row. Is there a way to do this without getting too cryptic?

解决方案

double[][] myArr = Enumerable
  .Range(0, rowCount)
  .Select(i => new double[colCount])
  .ToArray();

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