从字符串中删除数字 [英] Removing numbers from string

问题描述

如何从字符串中删除数字?

解决方案

这是否适合您的情况?

<预><代码>>>>s = '12abcd405'>>>result = ''.join([i for i in s if not i.isdigit()])>>>结果'A B C D'

这里使用了列表推导式，这里发生的事情类似于这个结构:

no_digits = []# 遍历字符串，将非数字添加到 no_digits 列表中对于我在 s:如果不是 i.isdigit():no_digits.append(i)# 现在用''连接列表的所有元素，# 将所有字符放在一起.结果 = ''.join(no_digits)

正如@AshwiniChaudhary 和@KirkStrauser 指出的那样，您实际上不需要在单行中使用括号，从而使括号内的部分成为生成器表达式(比列表理解更有效).即使这不符合您的作业要求，您最终也应该阅读它:) :

<预><代码>>>>s = '12abcd405'>>>result = ''.join(i for i in s if not i.isdigit())>>>结果'A B C D'

How can I remove digits from a string?

解决方案

Would this work for your situation?

>>> s = '12abcd405'
>>> result = ''.join([i for i in s if not i.isdigit()])
>>> result
'abcd'

This makes use of a list comprehension, and what is happening here is similar to this structure:

no_digits = []
# Iterate through the string, adding non-numbers to the no_digits list
for i in s:
    if not i.isdigit():
        no_digits.append(i)

# Now join all elements of the list with '', 
# which puts all of the characters together.
result = ''.join(no_digits)

As @AshwiniChaudhary and @KirkStrauser point out, you actually do not need to use the brackets in the one-liner, making the piece inside the parentheses a generator expression (more efficient than a list comprehension). Even if this doesn't fit the requirements for your assignment, it is something you should read about eventually :) :

>>> s = '12abcd405'
>>> result = ''.join(i for i in s if not i.isdigit())
>>> result
'abcd'

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