使用 findall 捕获组? [英] Capturing group with findall?

问题描述

如果我执行 findall(r'regex(with)capturing.goes.here') ，我如何访问捕获的组?我知道我可以通过 finditer 来完成，但我不想重复.

解决方案

findall 只返回捕获的组:

<预><代码>>>>re.findall('abc(de)fg(123)', 'abcdefg123 和 abcdefg123')[('de', '123'), ('de', '123')]

相关文档摘录:

<块引用>

返回所有不重叠的匹配项字符串中的模式，作为列表字符串.字符串被扫描从左到右，匹配是按找到的顺序返回.如果一个或更多的团体出现在模式，返回组列表；这将是元组列表，如果模式有不止一组.空的匹配项包含在结果中除非他们触及另一场比赛.

How can I access captured groups if I do findall(r'regex(with)capturing.goes.here') ? I know I can do it through finditer, but I don't want to iterate.

解决方案

findall just returns the captured groups:

>>> re.findall('abc(de)fg(123)', 'abcdefg123 and again abcdefg123')
[('de', '123'), ('de', '123')]

Relevant doc excerpt:

Return all non-overlapping matches of pattern in string, as a list of strings. The string is scanned left-to-right, and matches are returned in the order found. If one or more groups are present in the pattern, return a list of groups; this will be a list of tuples if the pattern has more than one group. Empty matches are included in the result unless they touch the beginning of another match.

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