从一组(相似的)字符串中确定前缀 [英] Determine prefix from a set of (similar) strings

问题描述

我有一组字符串，例如

my_prefix_what_ever
my_prefix_what_so_ever
my_prefix_doesnt_matter

我只想找到这些字符串的最长公共部分，这里是前缀.上面的结果应该是

I simply want to find the longest common portion of these strings, here the prefix. In the above the result should be

my_prefix_

字符串

my_prefix_what_ever
my_prefix_what_so_ever
my_doesnt_matter

应该导致前缀

my_

在 Python 中是否有一种相对轻松的方法来确定前缀(无需手动遍历每个字符)?

Is there a relatively painless way in Python to determine the prefix (without having to iterate over each character manually)?

PS:我使用的是 Python 2.6.3.

PS: I'm using Python 2.6.3.

推荐答案

永远不要重写提供给您的内容:os.path.commonprefix 正是这样做的:

Never rewrite what is provided to you: os.path.commonprefix does exactly this:

返回最长路径前缀(取逐个字符)，它是列表中所有路径的前缀.如果列出为空，返回空字符串 ('').请注意，这可能会返回无效路径，因为它一次处理一个字符.

Return the longest path prefix (taken character-by-character) that is a prefix of all paths in list. If list is empty, return the empty string (''). Note that this may return invalid paths because it works a character at a time.

为了与其他答案进行比较，代码如下:

For comparison to the other answers, here's the code:

# Return the longest prefix of all list elements.
def commonprefix(m):
    "Given a list of pathnames, returns the longest common leading component"
    if not m: return ''
    s1 = min(m)
    s2 = max(m)
    for i, c in enumerate(s1):
        if c != s2[i]:
            return s1[:i]
    return s1

这篇关于从一组(相似的)字符串中确定前缀的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！