如何用切片符号 a[::-1] 解释序列的反转 [英] How to explain the reverse of a sequence by slice notation a[::-1]
问题描述
切片索引有有用的默认值;省略的第一个索引默认为零,省略的第二个索引默认为被切片的字符串的大小.
<预><代码>>>>a = "你好">>>打印(a[::-1])奥列
正如教程所说 a[::-1]
应该等于 a[0:5:-1]
但是 a[0:5:-1]
为空如下:
问题不是 explain-slice-notation 的副本.这个问题是关于python中切片的一般用法.
我认为文档在这方面可能有点误导,但是切片的可选参数(如果省略)与使用 None
相同:
您可以从 CPython 字节码中看到以上 2 个切片是相同的:
<预><代码>>>>导入文件>>>dis.dis('a[::-1]') # 或 dis.dis('a[None:None:-1]')1 0 LOAD_NAME 0 (a)3 LOAD_CONST 0(无)6 LOAD_CONST 0(无)9 LOAD_CONST 2 (-1)12 BUILD_SLICE 315 BINARY_SUBSCR16 RETURN_VALUE对于负 step
,None
的替代值为 len(a) - 1
用于 start
> 和 -len(a) - 1
用于 end
:
这可能有助于您将其形象化:
he l l o0 1 2 3 4 5-6 -5 -4 -3 -2 -1
From the python.org tutorial
Slice indices have useful defaults; an omitted first index defaults to zero, an omitted second index defaults to the size of the string being sliced.
>>> a = "hello"
>>> print(a[::-1])
olleh
As the tutorial says a[::-1]
should equals to a[0:5:-1]
but a[0:5:-1]
is empty as follows:
>>> print(len(a[0:5:-1]))
0
The question is not a duplicate of explain-slice-notation. That question is about the general use of slicing in python.
I think the docs are perhaps a little misleading on this, but the optional arguments of slicing if omitted are the same as using None
:
>>> a = "hello"
>>> a[::-1]
'olleh'
>>> a[None:None:-1]
'olleh'
You can see that these 2 above slices are identical from the CPython bytecode:
>>> import dis
>>> dis.dis('a[::-1]') # or dis.dis('a[None:None:-1]')
1 0 LOAD_NAME 0 (a)
3 LOAD_CONST 0 (None)
6 LOAD_CONST 0 (None)
9 LOAD_CONST 2 (-1)
12 BUILD_SLICE 3
15 BINARY_SUBSCR
16 RETURN_VALUE
For a negative step
, the substituted values for None
are len(a) - 1
for the start
and -len(a) - 1
for the end
:
>>> a[len(a)-1:-len(a)-1:-1]
'olleh'
>>> a[4:-6:-1]
'olleh'
>>> a[-1:-6:-1]
'olleh'
This may help you visualize it:
h e l l o
0 1 2 3 4 5
-6 -5 -4 -3 -2 -1
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