如何从对象列表中提取特定属性列表? [英] How to extract from a list of objects a list of specific attribute?

问题描述

我有一个对象列表.对象有 3 个字符串属性.我想制作一个仅包含类中特定属性的列表.

I have a list of objects. Object has 3 string attributes. I want to make a list containing only a specific attribute from class.

是否有任何内置函数可以做到这一点?

Is there any built-in functions to do that?

推荐答案

列表推导式可以很好地工作:

A list comprehension would work just fine:

[o.my_attr for o in my_list]

但是有内置函数的组合，因为你问:-)

But there is a combination of built-in functions, since you ask :-)

from operator import attrgetter
map(attrgetter('my_attr'), my_list)

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