Re.match() 总是返回 none [英] Re.match() returns always none

问题描述

我觉得有点愚蠢，但它不起作用:

I feel kind of stupid but it does not work:

import re

a = " ebrj wjrbw erjwek wekjb rjERJK ABB RAEJKE BWE RWEJBEWJ B KREWBJ BWERBJ32J3B23B J BJ235JK BJJ523 2"

print re.match(ur'/(wekjb|ABB)/',a)
if re.match(ur'/(wekjb|ABB)/',a):
    print 'success'

如果用户给定的 a 是 unicode，我就有 ur'.如果 wekjb 或 ABB 在字符串中，我想打印成功，但我总是得到 None 作为 match.

I have the ur' if the user given a is unicode. I want to print success if wekjb or ABB is in the string but I always get None as the result of the match.

推荐答案

re.match 隐式锚定到字符串的开头.如果要在字符串中搜索可以位于其中任何位置的子字符串，则需要使用 re.search:

import re

a = " ebrj wjrbw erjwek wekjb rjERJK ABB RAEJKE BWE RWEJBEWJ B KREWBJ BWERBJ32J3B23B J BJ235JK BJJ523 2"

print re.search(ur'(wekjb|ABB)',a).group()
if re.search(ur'(wekjb|ABB)',a):
    print 'success'

输出:

wekjb
success

此外，Python 正则表达式的开头和结尾不需要 /.

Also, Python Regexes do not need to have a / at the start and end.

最后，我将 .group() 添加到 print 行的末尾，因为我认为这就是您想要的.否则，您会得到类似 <_sre.SRE_Match 对象在 0x01812220> 的东西，这不是很有用.

Lastly, I added .group() to the end of the print line because I think this is what you want. Otherwise, you'd get something like <_sre.SRE_Match object at 0x01812220>, which isn't too useful.

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