检查python中的type == list [英] Checking if type == list in python

问题描述

我可能在这里放屁了，但我真的不知道我的代码有什么问题:

I may be having a brain fart here, but I really can't figure out what's wrong with my code:

for key in tmpDict:
    print type(tmpDict[key])
    time.sleep(1)
    if(type(tmpDict[key])==list):
        print 'this is never visible'
        break

输出是 但 if 语句永远不会触发.有人能在这里发现我的错误吗?

the output is <type 'list'> but the if statement never triggers. Can anyone spot my error here?

推荐答案

您的问题是您之前在代码中将 list 重新定义为变量.这意味着当你执行 type(tmpDict[key])==list if 会返回 False 因为它们不相等.

Your issue is that you have re-defined list as a variable previously in your code. This means that when you do type(tmpDict[key])==list if will return False because they aren't equal.

话虽如此，您应该改用 isinstance(tmpDict[key], list) 测试某事物的类型时，这不会避免覆盖 list 的问题，而是一种更 Pythonic 的检查类型的方式.

That being said, you should instead use isinstance(tmpDict[key], list) when testing the type of something, this won't avoid the problem of overwriting list but is a more Pythonic way of checking the type.

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