如何在python中迭代文件 [英] How to iterate over the file in python

问题描述

我有一个包含一些十六进制数字的文本文件，我正在尝试将其转换为十进制.我可以成功转换它，但似乎在循环存在之前它读取了一些不需要的字符，所以我收到以下错误.

I have a text file with some hexadecimal numbers and i am trying to convert it to decimal. I could successfully convert it, but it seems before the loop exist it reads some unwanted character and so i am getting the following error.

Traceback (most recent call last):
  File "convert.py", line 7, in <module>
    print >>g, int(x.rstrip(),16)
ValueError: invalid literal for int() with base 16: ''

我的代码如下

f=open('test.txt','r')
g=open('test1.txt','w')
#for line in enumerate(f):  
while True:
    x=f.readline()
    if x is None: break
    print >>g, int(x.rstrip(),16)

每个十六进制数换行输入

Each hexadecimal number comes in a new line for input

推荐答案

回溯表明文件末尾可能有一个空行.你可以像这样修复它:

The traceback indicates that probably you have an empty line at the end of the file. You can fix it like this:

f = open('test.txt','r')
g = open('test1.txt','w') 
while True:
    x = f.readline()
    x = x.rstrip()
    if not x: break
    print >> g, int(x, 16)

另一方面，最好使用 for x in f 而不是 readline.不要忘记关闭您的文件或更好地使用 with 为您关闭它们:

On the other hand it would be better to use for x in f instead of readline. Do not forget to close your files or better to use with that close them for you:

with open('test.txt','r') as f:
    with open('test1.txt','w') as g: 
        for x in f:
            x = x.rstrip()
            if not x: continue
            print >> g, int(x, 16)

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