在 Python 中将 ASCII 代码列表转换为字符串(字节数组) [英] Convert list of ASCII codes to string (byte array) in Python
问题描述
我有一个整数 ASCII 值列表,我需要将其转换为字符串(二进制)以用作加密操作的密钥.(我正在python中重新实现java加密代码)
这有效(假设密钥为 8 字节):
key = struct.pack('BBBBBBBB', 17, 24, 121, 1, 12, 222, 34, 76)
但是,我不希望对密钥长度和 unpack() 参数列表进行硬编码.
给定初始整数列表,我该如何正确实现?
谢谢!
我更喜欢 array
模块到 struct
模块用于此类任务(涉及同类值序列的任务):
没有 len
调用,不需要字符串操作等——快速、简单、直接,为什么更喜欢其他方法?!
I have a list of integer ASCII values that I need to transform into a string (binary) to use as the key for a crypto operation. (I am re-implementing java crypto code in python)
This works (assuming an 8-byte key):
key = struct.pack('BBBBBBBB', 17, 24, 121, 1, 12, 222, 34, 76)
However, I would prefer to not have the key length and unpack() parameter list hardcoded.
How might I implement this correctly, given an initial list of integers?
Thanks!
I much prefer the array
module to the struct
module for this kind of tasks (ones involving sequences of homogeneous values):
>>> import array
>>> array.array('B', [17, 24, 121, 1, 12, 222, 34, 76]).tostring()
'\x11\x18y\x01\x0c\xde"L'
no len
call, no string manipulation needed, etc -- fast, simple, direct, why prefer any other approach?!
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