提取双引号之间的字符串 [英] Extract a string between double quotes

问题描述

我正在阅读来自期刊或论文来源的回复，我的 html 回复是一个字符串，例如:

<块引用>

根据一些人的说法，梦表达了人格的深刻方面"(Foulkes 184)，尽管其他人不同意.

我的目标只是从给定的字符串中提取所有引号并将它们保存到列表中.我的方法是:

[match.start() for m in re.Matches(inputString, "\"([^\"]*)\""))]

不知何故，它对我不起作用.对我的正则表达式有什么帮助吗?非常感谢.

解决方案

前提是没有嵌套引号:

re.findall(r'"([^"]*)"', inputString)

演示:

<预><代码>>>>进口重新>>>inputString = '根据一些人的说法，梦表达了人格的深刻方面"(Foulkes 184)，尽管其他人不同意.>>>re.findall(r'"([^"]*)"', inputString)['人格的深刻方面']

I'm reading a response from a source which is an journal or an essay and I have the html response as a string like:

According to some, dreams express "profound aspects of personality" (Foulkes 184), though others disagree.

My goal is just to extract all of the quotes out of the given string and save each of them into a list. My approach was:

[match.start() for m in re.Matches(inputString, "\"([^\"]*)\""))]

Somehow it didn't work for me. Any helps on my regex here? Thanks a lot.

解决方案

Provided there are no nested quotes:

re.findall(r'"([^"]*)"', inputString)

Demo:

>>> import re
>>> inputString = 'According to some, dreams express "profound aspects of personality" (Foulkes 184), though others disagree.'
>>> re.findall(r'"([^"]*)"', inputString)
['profound aspects of personality']

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