如何从 Python 中的一组字符串中删除特定的子字符串? [英] How to remove specific substrings from a set of strings in Python?

问题描述

我有一组字符串 set1，set1 中的所有字符串都有两个特定的子字符串，我不需要这些子字符串，也不想删除它们.
样本输入:set1={'Apple.good','Orange.good','Pear.bad','Pear.good','Banana.bad','Potato.bad'}
所以基本上我希望从所有字符串中删除 .good 和 .bad 子字符串.
我的尝试:

I have a set of strings set1, and all the strings in set1 have a two specific substrings which I don't need and want to remove.
Sample Input: set1={'Apple.good','Orange.good','Pear.bad','Pear.good','Banana.bad','Potato.bad'}
So basically I want the .good and .bad substrings removed from all the strings.
What I tried:

for x in set1:
    x.replace('.good','')
    x.replace('.bad','')

但这似乎根本不起作用.输出绝对没有变化，它与输入相同.我尝试使用 for x in list(set1) 而不是原始的，但这不会改变任何东西.

But this doesn't seem to work at all. There is absolutely no change in the output and it is the same as the input. I tried using for x in list(set1) instead of the original one but that doesn't change anything.

推荐答案

字符串是不可变的.str.replace 创建一个 <强>新字符串.文档中对此进行了说明:

Strings are immutable. str.replace creates a new string. This is stated in the documentation:

str.replace(old, new[, count])

返回字符串的副本，其中所有出现的子字符串 old 替换为 new.[...]

Return a copy of the string with all occurrences of substring old replaced by new. [...]

这意味着您必须重新分配集合或重新填充它(使用 集合理解):

This means you have to re-allocate the set or re-populate it (re-allocating is easier with a set comprehension):

new_set = {x.replace('.good', '').replace('.bad', '') for x in set1}

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