如何在 Python 中创建一个简单的多线程套接字服务器来记住客户端 [英] How to make a simple multithreaded socket server in Python that remembers clients

问题描述

如何制作一个简单的 Python 回显服务器，它可以记住客户端并且不会为每个请求创建一个新的套接字?必须能够支持并发访问.我希望能够使用此客户端或类似客户端连接一次并持续发送和接收数据:

How do I make a simple Python echo server that remembers clients and doesn't create a new socket for each request? Must be able to support concurrent access. I want to be able to connect once and continually send and receive data using this client or similar:

import socket

sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = raw_input("Server hostname or ip? ")
port = input("Server port? ")
sock.connect((host,port))
while True:
    data = raw_input("message: ")
    sock.send(data)
    print "response: ", sock.recv(1024)

即服务器在端口 50000 上运行，使用上面的客户端我希望能够做到这一点:

I.e. with the server running on port 50000, using the above client I want to be able to do this:

me@mine:~$ client.py
Server hostname or ip? localhost
Server Port? 50000
message: testa
response: testa
message: testb
response: testb
message: testc
response: testc

推荐答案

您可以为每个客户端使用一个线程来避免阻塞 client.recv() 然后使用主线程只监听新的客户.当一个连接时，主线程创建一个新线程，该线程只监听新客户端，并在 60 秒内不说话时结束.

You can use a thread per client to avoid the blocking client.recv() then use the main thread just for listening for new clients. When one connects, the main thread creates a new thread that just listens to the new client and ends when it doesn't talk for 60 seconds.

import socket
import threading

class ThreadedServer(object):
    def __init__(self, host, port):
        self.host = host
        self.port = port
        self.sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
        self.sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
        self.sock.bind((self.host, self.port))

    def listen(self):
        self.sock.listen(5)
        while True:
            client, address = self.sock.accept()
            client.settimeout(60)
            threading.Thread(target = self.listenToClient,args = (client,address)).start()

    def listenToClient(self, client, address):
        size = 1024
        while True:
            try:
                data = client.recv(size)
                if data:
                    # Set the response to echo back the recieved data 
                    response = data
                    client.send(response)
                else:
                    raise error('Client disconnected')
            except:
                client.close()
                return False

if __name__ == "__main__":
    while True:
        port_num = input("Port? ")
        try:
            port_num = int(port_num)
            break
        except ValueError:
            pass

    ThreadedServer('',port_num).listen()

客户端在 60 秒不活动后超时，必须重新连接.参见函数 ThreadedServer.listen()

Clients timeout after 60 seconds of inactivity and must reconnect. See the line client.settimeout(60) in the function ThreadedServer.listen()

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