从 tweepy 异常实例中获取错误代码 [英] Get the error code from tweepy exception instance

问题描述

我是 Python 新手，我正在尝试使用一个库.它引发了一个异常，我试图确定是哪一个.这就是我正在尝试的:

I'm new to python and I'm trying to use a library. It raises an exception, and I am trying to identify which one. This is what I am trying:

except tweepy.TweepError as e:
    print e
    print type(e)
    print e.__dict__
    print e.reason
    print type(e.reason)

这是我得到的:

[{u'message': u'Sorry, that page does not exist', u'code': 34}]
<class 'tweepy.error.TweepError'>
{'reason': u"[{u'message': u'Sorry, that page does not exist', u'code': 34}]", 'response': <httplib.HTTPResponse instance at 0x00000000029CEAC8>}
[{u'message': u'Sorry, that page does not exist', u'code': 34}]
<type 'unicode'>

我正在尝试使用该代码.我试过 e.reason.code 没有成功，我不知道该尝试什么.

Im trying to get to that code. I have tried e.reason.code with no success and I have no idea what to try.

推荐答案

这个怎么样?

except tweepy.TweepError as e:
    print e.message[0]['code']  # prints 34
    print e.args[0][0]['code']  # prints 34

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