Python正则表达式匹配字符串的中间 [英] Python regex match middle of string

问题描述

我有一个 python 字符串，我正在尝试提取它.我有一个有趣的问题:

<预><代码>>>>s="SKU 9780136058281, (ASIN B00A2KNZ2S, (装订商家:'平装书'/'精装书'))">>>打印(重新匹配('ASIN'，s))没有任何>>>打印(重新匹配('SKU'，s))<_sre.SRE_Match 对象;span=(0, 3), match='SKU'>

我正在尝试在 ASIN 后面添加一个数字.我仍然看不到明显的问题.它匹配行的开头，但不在中间.

解决方案

你需要使用 re.search 和 分组，注意 re.match 匹配字符串开头的模式:

<预><代码>>>>s="SKU 9780136058281, (ASIN B00A2KNZ2S, (装订商家:'平装书'/'精装书'))">>>进口重新>>>re.search(r'SKU (\d+)',s).group(1)'9780136058281'

r'SKU (\d+) 将匹配 SKU 之后长度为 1 或更多的任何数字组合 (\d)和一个空间！

I have a python string, that I'm trying to extract. I have a interesting issue:

>>> s="SKU 9780136058281, (ASIN B00A2KNZ2S, (binding Merchant: 'paperback' / 'hardcover'))"
>>> print(re.match('ASIN', s))
None
>>> print(re.match('SKU', s))
<_sre.SRE_Match object; span=(0, 3), match='SKU'>

I'm trying to mach a the number after ASIN. I can't still see a obvious problem. Its matching the beginning of the line, but not in the middle.

解决方案

You need to use re.search and grouping,and Note that re.match match the pattern from beginning of the string :

>>> s="SKU 9780136058281, (ASIN B00A2KNZ2S, (binding Merchant: 'paperback' / 'hardcover'))"
>>> import re
>>> re.search(r'SKU (\d+)',s).group(1)
'9780136058281'

r'SKU (\d+) will match any combination of digits (\d) with length 1 or more that came after SKU and a space!

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