比较 2 个列表中的相同索引 [英] Comparing same index in 2 lists

问题描述

我没有这方面的代码，因为我不知道该怎么做，并且在 Google 上找不到太多帮助.

I don't have a code for this because I have no idea how to do it, and couldn't find much help on Google.

有没有办法找出 2 个列表上的相同索引是否相同?

Is there a way to find if the same indexes on 2 lists are the same?

例如:

x_list = [1, 2, 3, 4, 5]
y_list = [1, 2, A, B, 5]

我想知道 X 的第一个索引是否与 Y 的第一个索引相同，X 的第二个索引是否与 Y 的第二个索引相同，等等.我可以这样做:

I want to know whether the first index of X is the same as the first index of Y, the second index of X is the same as the second index of Y, etc. I could do it like:

x_list[0] == y_list[0]

但需要一个无限的解决方案.

But need an infinite solution.

推荐答案

zip 列表并返回测试(返回一个布尔值作为结果):

zip the lists and return the test (which returns a boolean as outcome):

[i == j for i, j in zip(x_list, y_list)]

如果您不需要这些值，您可以使用 any 快速检查是否存在 False(意味着项目不相同):

You could use any to quickly check for the existence of a False (means the items are not the same) if you don't need the values:

any(i != j for i, j in zip(x_list, y_list))

一旦发现 False，any 版本就会中断，这意味着除了最坏的情况外，您可能不必遍历整个列表.

The any version would break once a False is found meaning you may not have to traverse the whole lists except in the worst case.

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