断言整数在范围内 [英] Assert an integer is within range
本文介绍了断言整数在范围内的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在用 python 编写一些单元测试来测试我是否收到一个整数.然而,有时这个整数可能会相差 1 或 2,我并不在乎.本质上,我希望能够断言接收到的整数在某个范围内,例如:
I am writing some unittests in python that are testing if I receive an integer. However sometimes this integer can be off by 1 or 2 and I don't really care. Essentially I want to be able to assert that the received integer is within a certain range, something like:
self.assertBetween(998, 1000, my_integer)
是否有一种可接受的方式来做到这一点?或者我必须做这样的事情:
Is there an accepted way of doing this? Or will I have to do something like this:
self.assertTrue(998 <= my_integer)
self.assertTrue(my_integer <= 1000)
编辑到目前为止的答案表明:
EDIT The answers so far suggest:
self.assertTrue(998 <= my_integer <= 1000)
与我的带有 2 个断言的示例相比,这有什么好处吗?
Is there any benefit of this over my example with 2 asserts?
推荐答案
您可以使用 "链式比较":
self.assertTrue(998 <= my_integer <= 1000)
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