删除确切的bash数组元素？ [英] delete exact bash array element?

问题描述

我想从一个bash数组中删除是任何一个关键字的首次亮相

I am trying to remove just the first appearance of any one keyword from a bash array.

ARRAY=(foo bar and any number of keywords)
keywords=(red, rednet, rd3.0)

我删除关键字如下： ARRAY =（$ {ARRAY [@] /$关键字/}）那么，如果红是第一个被发现的关键字，这将剥夺'的红色从两个关键字，并返回富巴网，而不是富红网吧。

I remove the keyword like this: ARRAY=( ${ARRAY[@]/"$keyword"/} ) then if "red' is the first found keyword, it will strip 'red' from both keywords and return "foo bar net" instead of "foo bar rednet".

编辑：下面是例子，希望这使得它更清晰。

Here is example, hopefully this makes it clearer.

for keyword in ${ARRAY[@]}; do
      if [ "$keyword" = "red" ] || [ "$keyword" = "rd3.0" ] || [ "$keyword" = "rednet" ]; then
           # HERE IS TROUBLE
           ARRAY=( ${ARRAY[@]/"$keyword"/} )
           echo "ARRAY is now ${ARRAY[@]}"
           break
      fi
 done

这要是 ARRAY =（红色红网rd3.0）收益净rd3.0 而不是红网rd3.0

如果我使用未设置,: 未设置$ {ARRAY [$关键字]} 如果rd3.0是数组在bash抱怨：：语法错误：无效的算术运算符（错误标记为.0）
什么是未设置或从阵列中删除只是完全匹配的安全方法？

If I use unset,: unset ${ARRAY["$keyword"]} bash complains if the rd3.0 is in the array: :syntax error: invalid arithmetic operator (error token is ".0") What is the safe way to unset or remove just an exact match from an array?

推荐答案

在指数使用与阵列值取消设置命令，是这样的：

Use the unset command with the array value at index, something like this:

#!/usr/bin/env bash
ARRAY=(foo bar any red alpha number of keywords rd3.0 and)
keywords=(red, rednet, rd3.0)

index=0
for keyword in ${ARRAY[@]}; do
      if [ "$keyword" = "red" ] || [ "$keyword" = "rd3.0" ] || [ "$keyword" = "rednet" ]; then
           # HERE IS TROUBLE
           # ARRAY=( ${ARRAY[@]/"$p"/} )
           unset ARRAY[$index]
           echo "ARRAY is now: ${ARRAY[@]}"
           break
      fi
      let index++
 done

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