更改字符串的时间格式 [英] change time format for a string

问题描述

我想写一个函数来改变时间格式，用一个偏移量来移动日期

I want to write a function to change the time format and an offset is used to shift the date

例如，我有一个字符串

"this is a string 2012-04-12 23:55 with a 2013-09-12 timezone"

我想把它改成类似

"**this is a string 20-Apr-2012 13:40 with a 19-Sep-2013 timezone**"

即数据的格式从yyyy-mm-dd变为dd-bbb-yyyy，日期偏移了.

That is, the format of the data change from yyyy-mm-dd to dd-bbb-yyyy and the date is shifted by offset.

我编写了以下函数，但它只给出这是一个字符串 20-Jun-2012 13:40，时区为 2013-11-12"

I write the following function but it only gives "this is a string 20-Jun-2012 13:40 with a 2013-11-12 timezone"

import re
import time
import datetime

def _deIDReportDate(report, offset=654321):
    redate = re.compile(r"""([0-9]+-[0-9]+-[0-9]+\s+[0-9]+:[0-9]+)|([0-9]+-[0-9]+-[0-9]+)""")
    match = redate.search(report)
    for match in redate.finditer(report):
        dt = match.group()
        if len(dt) > 10:
            dt = datetime.datetime.strptime(dt, '%Y-%m-%d %H:%M')
            dt += datetime.timedelta(seconds=offset)
            new_time = dt.strftime('%d-%b-%Y %H:%M')
            newReport = report[:match.start()] + new_time + report[match.end():]
            return newReport
        else:
            dt = datetime.datetime.strptime(dt, '%Y-%m-%d')
            dt += datetime.timedelta(seconds=offset)
            new_time = dt.strftime('%d-%b-%Y')
            newReport = report[:match.start()] + new_time + report[match.end():]
            return newReport

谁能帮助修复/改进我的代码?

Can anyone help to fix/improve my code?

推荐答案

你的错误是由于你试图调用 report.groups();您从未在 report 参数上应用正则表达式.

Your error is caused by you trying to call report.groups(); you never applied the regular expression on the report parameter.

您的代码可以显着简化:

Your code can be simplified significantly:

_dt = re.compile(r"""
    [12]\d{3}-   # Year (1xxx or 2xxx),
    [0-1]\d-     # month (0x, 1x or 2x)
    [0-3]\d      # day (0x, 1x, 2x or 3x)
    (?:\s        # optional: time after a space
        [0-2]\d: # Hour (0x, 1x or 2x)
        [0-5]\d  # Minute (0x though to 5x)
    )?
    """, flags=re.VERBOSE)

def _deIDReportDate(report, offset=654321):
    def replace(match):
        dt = match.group()

        if len(dt) > 10:
            # with time
            dt = datetime.datetime.strptime(dt, '%Y-%m-%d %H:%M')
            dt += datetime.timedelta(seconds=offset)
            return dt.strftime('%d-%b-%Y %H:%M')

        dt = datetime.datetime.strptime(dt, '%Y-%m-%d')
        dt += datetime.timedelta(seconds=offset)
        return dt.strftime('%d-%b-%Y')

    return _dt.sub(replace, report)

replace 嵌套函数为输入字符串中的每个非重叠匹配项调用.

The replace nested function is called for each non-overlapping match in the input string.

这篇关于更改字符串的时间格式的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！