在python中删除列表中的相邻元素 [英] Remove adjacent element in a list in python

问题描述

我正在尝试做一个简单的 python 程序来删除列表中的所有相邻元素

I am trying to do a simple python program that removes all the adjacent elements in a list

def main():
    a = [1, 5, 2, 3, 3, 1, 2, 3, 5, 6]
    c = len(a)

    for i in range (0, c-2):
        if a[i] == a[i+1]:
            del a[i]
            c = len(a)

    print a

if __name__ == '__main__':
    main()

输出为

[1, 5, 2, 3, 3, 2, 3, 5, 6] 没问题！

如果将 a 列表更改为 a = [1, 5, 2, 3, 3, 1, 2, 2, 5, 6]

If change the a list to a = [1, 5, 2, 3, 3, 1, 2, 2, 5, 6]

然后它给出一个错误

索引列表超出范围

**if a[i] == a[i+1]**

它不应该抱怨索引超出范围，因为我每次删除列表中的元素时都会计算 len(a).我在这里缺少什么?

It shouldn't be complaining about the index out of range as I am calculating the len(a) every time it deletes an element in the list. What am I missing here?

推荐答案

for i in range (0, c-2):

这不像其他语言中的 for 循环；它遍历 range 返回的列表(一次).以后更改c时，不会影响这个循环.

This is not like a for loop in some other languages; it’s iterating over a list returned (once) by range. When you change c later, it does not affect this loop.

你可以改用while:

c = len(a)

while i < c - 2:
    if a[i] == a[i + 1]:
        del a[i]
        c = len(a)
    else:
        i += 1

还有 itertools.groupby:

import itertools

def remove_consecutive(l):
    return (k for k, v in itertools.groupby(l))

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