检查关键字后是否有空格，如果在python中找到则中断 [英] Check if there is an empty space after a keyword and break if found in python

问题描述

我正在寻找一种方法来检查找到的关键字旁边是否有空格，如果有的话，中断循环，直到它再次找到关键字.

I am searching a way to check if there is a blank space next to the found keywords if so break the loop till it again finds the keyword.

例如这里，我有一个关键字:

For example here, I have a keyword:

'/* 函数声明 */'

'/* Function Declarations */'

如果找到此关键字，循环将继续进行并检查下一组关键字:

If this keyword is found the loop will proceed further and check for the next set of keywords:

['(const ', '(unsigned ', '(char ', '(double ', '(int ', '(long ', '(long long ', '(float ', '(string ','(签名', ');']

['(const ', '(unsigned ', '(char ', '(double ', '(int ', '(long ', '(long long ', '(float ', '(string ', '(signed ', ');']

如果这也满足，该行将被发送到另一个函数进行处理.直到有空位.这就是我想在这个函数中实现的.但不幸的是它忽略了空空间约束，只满足前两个

If this is also satisfied the line will be sent to another function for processing. Until there is an empty space. This is what I wanted to achieve in this function. But unfortunately it ignores the empty space constrain and it satisfies only the first two

我附上了这个函数:

def find_member_functions(opened_file, opened_cpp_file):

    previous_keyword = '/* Function Declarations */'

    member_func_keyword = ['(const ', '(unsigned ', '(char ',
                           '(double ', '(int ', '(long ',
                           '(long long ', '(float ', '(string ',
                           '(signed ', ');']

    for line in opened_cpp_file:
         prev_keyword_matched = [True for match in prev_keyword if match in line]
         if True in prev_keyword_matched:
             member_func_keyword_matched = [True for match in member_func_keyword if match in line]
             if True in member_func_keyword_matched: 
                 if line == '\n':
                     print "End of function declaration"
                     break
                 else:
                     found_funcs = member_functions(opened_file, line)
                     print str(found_funcs)
    return 

然后我编辑了我的代码，我无法实现我想要的.在这段代码中，它说一个空行成员函数结束"，即使它不是结束.我正在执行的行是

I then edited my code yet, I am not able to achieve what I wanted to. In this code, it says an empty line "End of member functions" even though it is not the end. The line which I am executing is

 /* Function Declarations */
  extern void multiplyImage(const unsigned char img[2115216], double parameter, 
  unsigned char imgout[2115216]);

  blabla.....

函数找到下一行作为空格虽然我有函数的延续

The functions finds the next line as a space though I have the continuation of the function

 unsigned char imgout[2115216]);

我编辑的代码:

def Find_Member_Functions(Opened_File, Opened_Cpp_File):
    Previous_Line_Keyword = '/* Function Declarations */'
    Member_Function_Keyword = ['(const ', '(unsigned ', '(char ', '(double ', '(int ', '(long ', '(long long ', '(float ', '(string ', '(signed ', ');']
    Empty_Line = ['\n', '\r\n']
    for item in Member_Function_Keyword:
        for line in Opened_Cpp_File:
            Previous_Line_Keyword_Matched = [True for match in Previous_Line_Keyword if match in line]
            if True in Previous_Line_Keyword_Matched:
                Member_Function_Keyword_Matched = [True for match in Member_Function_Keyword if match in line]
                if True in Member_Function_Keyword_Matched:  
                    Found_Functions = Member_Functions(Opened_File, line)
                    print str(Found_Functions)
                    Next_Line = line[1:]
                    Empty_Line_Matched = [True for match in Empty_Line if match in Next_Line]
                    if True in Empty_Line_Matched:
                        print "End of member functions"
                        break
                    else:
                        pass
    return 

我不明白我哪里出错了.有一些指导会很棒...

I couldn't understand where I am going wrong. It would be great to have some guidance...

我的命令行输出

extern void multiplyImage(const unsigned char img[2115216], double参数，

extern void multiplyImage(const unsigned char img[2115216], double parameter,

成员函数结束

无符号字符输出[2115216]);

unsigned char imgout[2115216]);

成员函数结束

推荐答案

这部分代码:

Next_Line = line[1:]
Empty_Line_Matched = [True for match in Empty_Line if match in Next_Line]

完全没有意义，主要有以下三个原因:

Makes absolutely no sense, for three principal reasons:

1. line[1:] 不是下一行，它只是同一行减去第一个字符；
2. 对于空行line == '\n'，第一个字符是'\n'，所以line[1:] == "" 因此 Next_Line 不 包含换行符；和
3. '\n' 位于每一行的末尾，所以 Empty_Line_Matched 将包含 Truecase 除了一个空行(见#2).

1. line[1:] isn't the next line, it's just same line less its first character;
2. For blank lines line == '\n', the first character is '\n', so line[1:] == "" and therefore Next_Line doesn't contain a newline character; and
3. '\n' is at the end of every line, so Empty_Line_Matched will contain True in every case except a blank line (see #2).

这篇关于检查关键字后是否有空格，如果在python中找到则中断的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！