PHP / MySQL的 - 对于机器人的数组过滤器 [英] PHP/MySQL - an array filter for bots

问题描述

我在做一个计数器。我有一个数据库，我存储的IP地址和 $ _ SERVER ['HTTP_USER_AGENT'];参观者。现在，我需要添加一个过滤器，这样我就可以收起命中，由机器人进行。我发现，很多僵尸通常会保留一些常用词语的 $ _ SERVER ['HTTP_USER_AGENT']; ，所以我的喜欢做和文字的排列，这将保持机器人从结果中显示。

I'm making a hit counter. I have a database and I store the IP and $_SERVER['HTTP_USER_AGENT']; of the visitors. Now I need to add a filter, so I can put away the hits, that are made by bots. I found out, that many bots usually keep some common words in the $_SERVER['HTTP_USER_AGENT']; , so I's like to make and array of words, that would keep the bot from displaying in the results.

这是我现在有：

while($row = mysql_fetch_array($yesterday, MYSQL_ASSOC)) {

＆LT; - 在这里，我需要一个code，这将通过阵列上运行，检查，
如果containts的关键字，如果它不...算了算++; - >

<-- Here I need a code, that would run through an array and check, if it containts the keywords and if it doesn't ... just count++; -->

	}

另外，如果你知道的检测和删除的结果机器人任何其他方式，我很感激柠。干杯

Also if you know any other way of detecting and removing the bots from the results, I'd be verry thankful. Cheers

推荐答案

遍历字的阵列的foreach ，并检查是否使用了UA字符串存在当前字 strpos（）：

Loop through the array of words with foreach and check if the current word exists in the UA string using strpos():

foreach ($words as $word) {
    if (strpos($row['user_agent'], $word) !== FALSE) {
        // word exists in string
    }
}

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