Tornado request.body [英] Tornado request.body

问题描述

我的 Tornado 应用程序通过 http body 请求接受 POST 数据

My Tornado application accepts POST data through http body request

在我的处理程序中，我能够收到请求

In my handler I am able to get the request

def post(self):
    data = self.request.body

我得到的数据来自 str(dictionary)

The data I am getting is in the from of str(dictionary)

有没有办法以 Python 字典的形式接收这些数据?

Is there a way to receive this data in the form of a Python dictionary?

我不想在服务器端使用 eval 将此字符串转换为 Python 字典.

I don't want to use eval on the server side to convert this string to a Python dictionary.

推荐答案

作为 Eloim 答案的替代方案，Tornado 提供了 tornado.escape 用于转义/取消转义 HTML、JSON、URL 和其他".使用它应该给你你想要的:

As an alternative to Eloim's answer, Tornado provides tornado.escape for "Escaping/unescaping HTML, JSON, URLs, and others". Using it should give you exactly what you want:

data = tornado.escape.json_decode(self.request.body)

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