琴弦为什么表现得像在PHP 5.3数组？ [英] Why do strings behave like an array in PHP 5.3?

问题描述

我有这样的code：

$tierHosts['host'] = isset($host['name']) ? $host['name'] : $host;

它的正常工作在PHP 5.5，但在PHP 5.3的条件下返回true，而 $主机包含像 pjba01 。它返回的第一个字母 $ tierHosts ['主机'] ，即 P 。

It's working fine in PHP 5.5, but in PHP 5.3 the condition returns true while $host contains a string like pjba01. It returns the first letter of $tierHosts['host'], that is, p.

这有什么错我的code？

What's so wrong with my code?

推荐答案

的您可以访问字符串像数组和以前的PHP 5.4偏移喜欢你的名称被静静地铸造为0，意味着你访问该字符串的第一个字符：

You can access strings like an array and prior PHP 5.4 offsets like your name were silently casted to 0, means you accessed the first character of that string:

character | p | j | b | a | 0 | 1 |
-----------------------------------
index     | 0 | 1 | 2 | 3 | 4 | 5 |

在5.3这样的偏移将抛出一个通知，你还可以在手册中读到：

After 5.3 such offsets will throw a notice, as you can also read in the manual:

随着PHP 5.4字符串偏移量必须要么是整数或整数样的字符串，否则警告将被抛出。 previously一个像富偏移悄悄转换为0。

As of PHP 5.4 string offsets have to either be integers or integer-like strings, otherwise a warning will be thrown. Previously an offset like "foo" was silently cast to 0.

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