在Java中，如何更有效地追加一个字符串？ [英] In Java, how to append a string more efficiently?

问题描述

我写了一个Java程序，其中，我需要追加一个字符串

I wrote a Java program, in which, I need to append a string

u13a2到现有的u1234 u12de u1386 ... u15a3。

所以渐渐串越来越长。我发现，花在每个追加也变得越来越长的时间。有没有什么办法，我们可以改善这在某种程度上？

So gradually the string becomes longer and longer. I found the time spent on each appending also becomes longer and longer. Is there any way that we can improve this to some extend ?

实施来到我的脑海包括：

The implementation came to my mind includes:

unicodeArray += " "+unicode;

或

unicodeArray = unicodeArray.concat(" "+unicode);

他们给类似的性能。我认为，导致这些不良绩效的主要的原因是特殊类型的字符串。它为每一个分配一个新的对象。如果你也是这么认为的，这是否意味着我最好用另一种类型，如字节数组？

They gave similar performance. I think the main reason that causes these bad performance is the special type String. It creates a new object for every assignment. If you also think so, does this mean I'd better use another type, like byte array?

推荐答案

使用<一个href=\"http://docs.oracle.com/javase/6/docs/api/java/lang/StringBuilder.html\"><$c$c>StringBuilder类。它是什么，你正在尝试做的更有效率。

Use StringBuilder class. It is more efficient at what you are trying to do.

这篇关于在Java中，如何更有效地追加一个字符串？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！