返回可变数量输出的python函数 [英] python function that returns a variable number of outputs

问题描述

我想输入一个未知宽度(列数)的表格，并且我希望我的函数为每列输出一个列表.我还输出了一个包含上述列表名称的列表.

I want to input a table of unknown width (number of columns) and I want my function to output a list for each column. I am also outputting a list containing the names of the said lists.

我正在尝试:

def crazy_fn(table):  
    titles=read_col_headers(table)  
    for i in range(1,len(table)):   
        for j in range(0,len(titles)):  
            vars()[titles[j]].append(table[i][j])  

    return titles, vars()[titles[k]] for k in range(0,len(titles))

当我知道我将输出多少列/列表(返回标题、a、b、c、d)时，该函数有效，但我试图概括的方式不起作用.

The function works for when I know how many columns/lists I will output (return titles, a, b, c, d), but the way I've tried to generalize is not working.

推荐答案

让函数返回的变量数量非常多通常是个坏主意，因为使用它会造成混淆且容易出错.

It's generally a bad idea to have a non-constant number of variables returned from a function, because using it is confusing and error-prone.

为什么不返回映射标题标题到列表的字典?

Why don't you return a dictionary mapping title headers to the list?

def crazy_fn(table):  
    result=dict()
    titles=read_col_headers(table)
    for title in titles:
        result[title]=VALUE(TITLE)
    return result

这可以使用字典理解来缩写为:

This can be abbreviated using dictionary comprehension to:

def crazy_fn(table):
   return {title : VALUE(TITLE) for title in read_col_headers(table)}

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