tkinter 选项菜单 - 即时更新选项 [英] tkinter option menu - update options on fly

问题描述

我正在使用 Tkinter 和 Python 2.7.6 创建一个 GUI.

I'm creating a GUI using Tkinter with Python 2.7.6.

我有一个下拉菜单，使用以下代码创建并最初禁用:

I have a drop down menu, created and initially disabled with the following code:

    self.dropdown = Tkinter.OptionMenu(self, self.dropdownVar, "Select SED...")
    self.dropdown.grid(column=0,row=1)
    self.dropdown.configure(state="disabled")

在用户选择一个目录后，我调用一个函数 onEnterDir()，然后它会获取该目录中的文件列表.所以，我有一个名为 dirFiles 的变量中的文件列表.

After a user selects a directory, I call a function onEnterDir() which then gets a list of files in that directory. So, I have a list of files in a variable called dirFiles.

我想要的是使用此 dirFiles 列表中的项目更新下拉菜单中的选项.我该怎么做?

What I want is to then update the options in the dropdown menu with the items in this dirFiles list. How would I do this?

我的问题与这里的其他人不同，因为我只想更新 self.dropdown 显示的项目列表.它不依赖于任何其他小部件.我有一个想要放入的内容的 Python 列表.我该怎么做?

My question is different to others on here because I just want to update the list of items self.dropdown displays. It's not dependent on any other widget. I have a python list of things I want to put in. How do I do this?

推荐答案

您可以在 您在问题中提到的答案:

例如:

import os
from functools import partial
from Tkinter import *
from tkFileDialog import askdirectory

def onEnterDir(dropdown, var):
    path = askdirectory()
    if not path:
        return
    filenames = os.listdir(path)
    dropdown.configure(state='normal')  # Enable drop down
    menu = dropdown['menu']

    # Clear the menu.
    menu.delete(0, 'end')
    for name in filenames:
        # Add menu items.
        menu.add_command(label=name, command=lambda name=name: var.set(name))
        # OR menu.add_command(label=name, command=partial(var.set, name))


root = Tk()
dropdownVar = StringVar()
dropdown = OptionMenu(root, dropdownVar, "Select SED...")
dropdown.grid(column=0, row=1)
dropdown.configure(state="disabled")
b = Button(root, text='Change directory',
           command=lambda: onEnterDir(dropdown, dropdownVar))
b.grid(column=1, row=1)
root.mainloop()

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