Python:如何使用 popen 在一个进程中运行多个命令 [英] Python: How to run multiple commands in one process using popen

问题描述

我想打开一个进程并在同一个进程中运行两个命令.我有:

I want to open a process and run two commands in the same process. I have :

cmd1 = 'source /usr/local/../..'
cmd2 = 'ls -l'
final = Popen(cmd2, shell=True, stdin=PIPE, stdout=PIPE, stderr=STDOUT, close_fds=True)
stdout, nothing = final.communicate()
log = open('log', 'w')
log.write(stdout)
log.close()

如果我两次使用popen，这两个命令会在不同的进程中执行.但我希望它们在同一个 shell 中运行.

If I use popen two times, these two commands will be executed in different processes. But I want them to run in the same shell.

推荐答案

这些命令将始终是两个 (unix) 进程，但您可以通过对 Popen 和同一个 shell 的一次调用来启动它们使用:

The commands will always be two (unix) processes, but you can start them from one call to Popen and the same shell by using:

from subprocess import Popen, PIPE, STDOUT

cmd1 = 'echo "hello world"'
cmd2 = 'ls -l'
final = Popen("{}; {}".format(cmd1, cmd2), shell=True, stdin=PIPE, 
          stdout=PIPE, stderr=STDOUT, close_fds=True)
stdout, nothing = final.communicate()
log = open('log', 'w')
log.write(stdout)
log.close()

运行程序后，文件日志"包含:

After running the program the file 'log' contains:

hello world
total 4
-rw-rw-r-- 1 anthon users 303 2012-05-15 09:44 test.py

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