将参数传递给 PyRun_File(***) [英] Pass argument to PyRun_File(***)

问题描述

我正在用 C 和 Python 编写一些代码.

I am writing some code in C and in Python.

我有一个名为 sample.py 的 python 文件，它接受两个字符串参数.

I have a python file called sample.py which accepts two string parameters.

我的 C 程序使用 PyRun_SimpleString() 调用 python 函数.这样我就无法传递任何参数.

My C program calls the python function using the PyRun_SimpleString(). In this way I am not able to pass any parameters.

通过PyRun_SimpleString():

int main(int argc,char *argv[])
{
 ......
PyRun_SimpleString("import sample\nsample.mainfunc("argv[1]",'Isolated_domU_t')\n");
.....
}

如何使用PyRun_SimpleString(*) 传递参数argv[1]?

推荐答案

要设置参数，请执行以下代码:

To set arguments do like the following code:

wchar_t** wargv = new wchar_t*[argc];
for(int i = 0; i < argc; i++)
{
    wargv[i] = Py_DecodeLocale(argv[i], nullptr);
    if(wargv[i] == nullptr)
    {
        return EXIT_FAILURE;
    }
}

Py_Initialize();

// char* py=...
PySys_SetArgv(argc, wargv);
PyRun_SimpleString(py);

Py_Finalize();

for(int i = 0; i < argc; i++)
{
    PyMem_RawFree(wargv[i]);
    wargv[i] = nullptr;
}

delete[] wargv;
wargv = nullptr;

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