Python字符旋转 [英] Python character rotation

问题描述

你能帮我写一个函数，它接收一个字符char(即长度为1的字符串)和一个整数旋转.我的函数应该返回一个长度为 1 的新字符串，这是通过向右旋转位置数旋转字符的结果.我这段代码的输出应该是这样的:

Could you please help me with writing a function, which receives a character char (ie., a string of length one ), and an integer rotation. My function should return a new string of length one, the resulting of rotating char by rotation number of places to the right. My output for this code should be like this:

print(alphabet_position(a, 13)) = Output = n
print(alphabet_position(A, 14)) = Output = (capital) O
print(alphabet_position(6, 13)) = Output = 6

我的函数是这样的

 def alphabet_position(letter, number):
    for char in letter:
        return ord(char)+ number
print(alphabet_position("g", 2))
print(alphabet_position("Z", 2))

输出为 105输出为 92

The output is 105 The output is 92

推荐答案

你忘了做你提到的检查，而且，你需要使用 chr(returnedValue) 将返回的整数转换为字符.查看以下函数代码:

def alphabet_position(letter, number):
    if len(letter) != 1:
        return -1 #Invalid input
    elif letter.isalpha() == False:
        return letter #If its not an alphabet
    else:
        ans = ord(letter) + number
        # the below if-statement makes sure the value does not overflow.
        if ans > ord('z') and letter.islower():
            ans = ans - ord('z') + ord('a')
        elif ans > ord('Z') and letter.isupper():  
            ans = ans - ord('Z') + ord('A')
        return chr(ans)

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