无法交换列表中的元素,Python [英] Can't swap the elements in a list, Python
本文介绍了无法交换列表中的元素,Python的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试使用 while 循环交换列表中的元素.这样函数一次只能交换两个连续的元素.并用列表中的可能列表返回给我,但它只打印一个可能的路径.
I am trying to swap elements in a list using while loop. So that the function can only swap two consecutive elements at a time. And return me with the possible list in a list, But it's only printing one possible path.
初始列表为[4,3,2,1]
The initial list is[4,3,2,1]
预期输出 = [[3,4,2,1], [4,2,3,1],[4,3,1,2]]
Expected Output = [[3,4,2,1], [4,2,3,1],[4,3,1,2]]
电流输出 = [[3,2,1,4],[3,2,1,4],[3,2,1,4]]
Current Output = [[3,2,1,4],[3,2,1,4],[3,2,1,4]]
我的代码是
array = [4,3,2,1]
def possible_paths(Array):
temp_arr = []
i=0
while i < (len(Array) -1):
temp1 = Array[i]
Array[i] = Array[i+1]
Array[i+1] = temp1
temp_arr.append(Array)
i = i+1
return temp_arr
arr1 = []
poss = possible_paths(array)
arr1.append(poss)
print(arr1[:])
推荐答案
array = [4,3,2,1]
def possible_paths(Array):
temp_arr = []
i=0
while i < (len(Array) -1):
clone_array = Array[:]
clone_array[i], clone_array[i+1] = clone_array[i+1], clone_array[i]
temp_arr.append(clone_array)
i = i+1
return temp_arr
poss = possible_paths(array)
print(poss)
输出:[[3, 4, 2, 1], [4, 2, 3, 1], [4, 3, 1, 2]]
Output : [[3, 4, 2, 1], [4, 2, 3, 1], [4, 3, 1, 2]]
这篇关于无法交换列表中的元素,Python的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文