如何替换多维数组中的值? [英] How to replace values in multidimensional array?

问题描述

我正在尝试使多维数组工作，其中用户字符串填充在单元格中.我一直在寻找更新多维数组中用户值的方法

 def createMultiArray(self,usrstrng,Itmval):#创建一个多维数组，其中usrstrng=用户输入，Itmval=widthArrayMulti=[[" " for x in range(Itmval)]for x in range(Itmval)]# 需要更新用户值，因此访问索引来更新值.对于 ArrayMulti 中的行:对于范围内的索引(len(行)):对于 usrstrng 中的 Usrchr:行[索引]= Usrchrprint "这是更新的数组>>>",ArrayMulti

输入

 乐趣

我得到的当前输出

 这是更新的数组>>>[['s', 's', 's'], ['s', 's', 's'], ['s', 's', 's']]

我在找什么

 这是更新的数组>>>[['f', 'u', 'n'], ['s', ' ', ' '], [' ', ' ', ' ']]

空格可以用*填

解决方案

string.replace 不起作用，因为它不影响原始值.

<预><代码>>>>测试 = "你好">>>test.replace("a", " ")'你好'>>>测试'你好'

相反，您需要通过索引访问列表:

 用于 ArrayMulti 中的行:对于范围内的索引(len(行)):行[索引] = "a"

如果您提供更精确的问题并将您想要达到的输出添加到问题中，我可以给您更精确的答案.

我废弃了之前的解决方案，因为它不是您想要的

def UserMultiArray(usrstrng, Itmval):ArrayMulti=[[" " for x in range(Itmval)] for x in range(Itmval)]对于索引，枚举中的字符(usrstrng):ArrayMulti[index//Itmval][index%Itmval] = char返回 ArrayMulti>>>stack.UserMultiArray("乐趣", 3)[['f', 'u', 'n'], ['s', ' ', ' '], [' ', ' ', ' ']]

这个小技巧使用整数除法:

<块引用>

[0, 1 ,2 ,3 ,4]//3 -> 0, 0, 0, 1, 1

和模运算符(https://en.wikipedia.org/wiki/Modulo_operation):

<块引用>

[0, 1 ,2 ,3 ,4] % 3 -> 0, 1, 2, 0, 1

I am trying to get a multidimensional array working, where the user string is filled in the cell. I have been searching for ways to update user values in the multidimensional array

  def createMultiArray(self,usrstrng,Itmval):
    #creates a multidimensional array, where usrstrng=user input, Itmval=width        
    ArrayMulti=[[" " for x in range(Itmval)]for x in range(Itmval)]

    # need to update user values, therefore accessing index to update values.
    for row in ArrayMulti:
        for index in range(len(row)):

            for Usrchr in usrstrng:
                row[index]= Usrchr
    print "This is updated array>>>",ArrayMulti

Input

  funs

current output that i am getting

  This is updated array>>> [['s', 's', 's'], ['s', 's', 's'], ['s', 's', 's']]

what i am looking for

  This is updated array>>> [['f', 'u', 'n'], ['s', ' ', ' '], [' ', ' ', ' ']]

the blank can be filled in with *

解决方案

string.replace won't work, since it does not affect the original value.

>>> test = "hallo"
>>> test.replace("a", " ")
'h llo'
>>> test
'hallo'

Instead you need to access the list via the indexes:

for row in ArrayMulti:
    for index in range(len(row)):
        row[index] = "a"

If you provide a more precise question and add the output you want to achieve to the question, I can give you a more precise answer.

I scrapped the previous solution since it wasn't what you wanted

def UserMultiArray(usrstrng, Itmval):
    ArrayMulti=[[" " for x in range(Itmval)] for x in range(Itmval)]

    for index, char in enumerate(usrstrng):
        ArrayMulti[index//Itmval][index%Itmval] = char
    return ArrayMulti


>>> stack.UserMultiArray("funs", 3)
[['f', 'u', 'n'], ['s', ' ', ' '], [' ', ' ', ' ']]

This little trick uses the whole-number-division:

[0, 1 ,2 ,3 ,4] // 3 -> 0, 0, 0, 1, 1

and the modulo operator(https://en.wikipedia.org/wiki/Modulo_operation):

[0, 1 ,2 ,3 ,4] % 3 -> 0, 1, 2, 0, 1

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