倒计时:01:05 [英] Countdown Clock: 01:05

问题描述

如何在 Python 中创建一个看起来像 00:00(分 & 秒)的倒计时时钟，它在自己的一行上.每次它减少一实际秒，那么旧的计时器应该在其行上替换为一个低一秒的新计时器:01:00 变成了 00:59 并且它实际上命中了 00:00.

How can I create a countdown clock in Python that looks like 00:00 (min & sec) which is on a line of its own. Every time it decreases by one actual second then the old timer should be replaced on its line with a new timer that is one second lower: 01:00 becomes 00:59 and it actually hits 00:00.

这是我开始使用但想要转换的基本计时器:

Here is a basic timer I started with but want to transform:

def countdown(t):
    import time
    print('This window will remain open for 3 more seconds...')
    while t >= 0:
        print(t, end='...')
        time.sleep(1)
        t -= 1
    print('Goodbye! \n \n \n \n \n')

t=3

我还想确保 Goodbye! 之后的任何内容(最有可能在函数之外)都在它自己的行上.

I also want to make sure that anything after Goodbye! (which would most likely be outside of the function) will be on its own line.

结果: 3...2...1...0...再见！

我知道这与其他倒计时问题类似，但我相信它有其独特之处.

I know this is similar to other countdown questions but I believe that it has its own twist.

推荐答案

除了将时间格式化为分钟和秒之外，您还需要打印回车.将 end 设置为 \r:

Apart from formatting your time as minutes and seconds, you'll need to print a carriage return. Set end to \r:

import time

def countdown(t):
    while t:
        mins, secs = divmod(t, 60)
        timeformat = '{:02d}:{:02d}'.format(mins, secs)
        print(timeformat, end='\r')
        time.sleep(1)
        t -= 1
    print('Goodbye!\n\n\n\n\n')

这可确保 next 打印覆盖最后一行打印:

This ensures that the next print overwrites the last line printed:

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