查找字符串中所有出现的字符 [英] Find all occurrences of a character in a String

问题描述

我对 Python 真的很陌生，正在尝试构建一个 Hangman 游戏以供练习.

我正在使用 Python 3.6.1

用户可以输入一个字母，我想告诉他单词中是否出现了该字母以及它在哪里.

我通过使用 occurrences = currentWord.count(guess) 得到总出现次数

我有 firstLetterIndex = (currentWord.find(guess)) 来获取索引.

现在我有了第一个字母的索引，但是如果这个词多次出现这个字母怎么办?
我试过 secondLetterIndex = (currentWord.find(guess[firstLetterIndex, currentWordlength]))，但这不起作用.
有一个更好的方法吗?也许我找不到内置功能?

I'm really new to python and trying to build a Hangman Game for practice.

I'm using Python 3.6.1

The User can enter a letter and I want to tell him if there is any occurrence of that letter in the word and where it is.

I get the total number of occurrences by using occurrences = currentWord.count(guess)

I have firstLetterIndex = (currentWord.find(guess)), to get the index.

Now I have the index of the first Letter, but what if the word has this letter multiple times?
I tried secondLetterIndex = (currentWord.find(guess[firstLetterIndex, currentWordlength])), but that doesn't work.
Is there a better way to do this? Maybe a build in function i can't find?

推荐答案

一种方法是使用列表推导式查找索引:

One way to do this is to find the indices using list comprehension:

currentWord = "hello"

guess = "l"

occurrences = currentWord.count(guess)

indices = [i for i, a in enumerate(currentWord) if a == guess]

print indices

输出:

[2, 3]

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